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1140441313313 = 6717021512139
BaseRepresentation
bin10000100110000111100…
…110010111000000100001
311001000200022112100021202
4100212013212113000201
5122141110434011223
62231524515130545
7145252125135041
oct20460746270041
94030608470252
101140441313313
113aa727432285
121650375a3a55
138370a405673
143d2aa511721
151e9eb0ac428
hex10987997021

1140441313313 has 4 divisors (see below), whose sum is σ = 1157462825520. Its totient is φ = 1123419801108.

The previous prime is 1140441313303. The next prime is 1140441313327. The reversal of 1140441313313 is 3133131440411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1140441313313 - 222 = 1140437119009 is a prime.

It is a super-2 number, since 2×11404413133132 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1140441313303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8510756003 + ... + 8510756136.

It is an arithmetic number, because the mean of its divisors is an integer number (289365706380).

Almost surely, 21140441313313 is an apocalyptic number.

It is an amenable number.

1140441313313 is a deficient number, since it is larger than the sum of its proper divisors (17021512207).

1140441313313 is an equidigital number, since it uses as much as digits as its factorization.

1140441313313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17021512206.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 1140441313313 its reverse (3133131440411), we get a palindrome (4273572753724).

The spelling of 1140441313313 in words is "one trillion, one hundred forty billion, four hundred forty-one million, three hundred thirteen thousand, three hundred thirteen".

Divisors: 1 67 17021512139 1140441313313