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114044232121 = 311366701711
BaseRepresentation
bin110101000110110010…
…0001110000110111001
3101220100221100020212221
41222031210032012321
53332030310411441
6124220255404041
711145056656441
oct1521544160671
9356327306787
10114044232121
1144402aa5606
121a129223621
13a9a6337571
14573c36d121
152e771a88d1
hex1a8d90e1b9

114044232121 has 4 divisors (see below), whose sum is σ = 114410934144. Its totient is φ = 113677530100.

The previous prime is 114044232061. The next prime is 114044232139. The reversal of 114044232121 is 121232440411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114044232121 - 213 = 114044223929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114044232821) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183350545 + ... + 183351166.

It is an arithmetic number, because the mean of its divisors is an integer number (28602733536).

Almost surely, 2114044232121 is an apocalyptic number.

It is an amenable number.

114044232121 is a deficient number, since it is larger than the sum of its proper divisors (366702023).

114044232121 is an equidigital number, since it uses as much as digits as its factorization.

114044232121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 366702022.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 114044232121 its reverse (121232440411), we get a palindrome (235276672532).

The spelling of 114044232121 in words is "one hundred fourteen billion, forty-four million, two hundred thirty-two thousand, one hundred twenty-one".

Divisors: 1 311 366701711 114044232121