Base | Representation |
---|---|
bin | 110101000110111110… |
… | …0010000111110100011 |
3 | 101220101101012111021011 |
4 | 1222031330100332203 |
5 | 3332033414112311 |
6 | 124221042441351 |
7 | 11145164361235 |
oct | 1521574207643 |
9 | 356341174234 |
10 | 114050535331 |
11 | 44406610277 |
12 | 1a12b363257 |
13 | a9a7733585 |
14 | 573d130255 |
15 | 2e77a01321 |
hex | 1a8df10fa3 |
114050535331 has 2 divisors, whose sum is σ = 114050535332. Its totient is φ = 114050535330.
The previous prime is 114050535317. The next prime is 114050535343. The reversal of 114050535331 is 133535050411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114050535331 - 223 = 114042146723 is a prime.
It is a super-2 number, since 2×1140505353312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114050535293 and 114050535302.
It is not a weakly prime, because it can be changed into another prime (114050535311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57025267665 + 57025267666.
It is an arithmetic number, because the mean of its divisors is an integer number (57025267666).
Almost surely, 2114050535331 is an apocalyptic number.
114050535331 is a deficient number, since it is larger than the sum of its proper divisors (1).
114050535331 is an equidigital number, since it uses as much as digits as its factorization.
114050535331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 114050535331 its reverse (133535050411), we get a palindrome (247585585742).
The spelling of 114050535331 in words is "one hundred fourteen billion, fifty million, five hundred thirty-five thousand, three hundred thirty-one".
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