Base | Representation |
---|---|
bin | 110101000110111110… |
… | …0010000111111001011 |
3 | 101220101101012111022122 |
4 | 1222031330100333023 |
5 | 3332033414112441 |
6 | 124221042441455 |
7 | 11145164361323 |
oct | 1521574207713 |
9 | 356341174278 |
10 | 114050535371 |
11 | 44406610303 |
12 | 1a12b36328b |
13 | a9a77335b6 |
14 | 573d130283 |
15 | 2e77a0134b |
hex | 1a8df10fcb |
114050535371 has 2 divisors, whose sum is σ = 114050535372. Its totient is φ = 114050535370.
The previous prime is 114050535343. The next prime is 114050535397. The reversal of 114050535371 is 173535050411.
It is a strong prime.
It is an emirp because it is prime and its reverse (173535050411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114050535371 - 222 = 114046341067 is a prime.
It is not a weakly prime, because it can be changed into another prime (114050535311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57025267685 + 57025267686.
It is an arithmetic number, because the mean of its divisors is an integer number (57025267686).
Almost surely, 2114050535371 is an apocalyptic number.
114050535371 is a deficient number, since it is larger than the sum of its proper divisors (1).
114050535371 is an equidigital number, since it uses as much as digits as its factorization.
114050535371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31500, while the sum is 35.
Adding to 114050535371 its reverse (173535050411), we get a palindrome (287585585782).
The spelling of 114050535371 in words is "one hundred fourteen billion, fifty million, five hundred thirty-five thousand, three hundred seventy-one".
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