114101533141433 has 4 divisors (see below), whose sum is σ = 114922407480720. Its totient is φ = 113280658802148.

The previous prime is 114101533141429. The next prime is 114101533141451. The reversal of 114101533141433 is 334141335101411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114101533141433 - 2² = 114101533141429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114101533141393 and 114101533141402.

It is not an unprimeable number, because it can be changed into a prime (114101533101433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 410437169435 + ... + 410437169712.

It is an arithmetic number, because the mean of its divisors is an integer number (28730601870180).

Almost surely, 2^{114101533141433} is an apocalyptic number.

It is an amenable number.

114101533141433 is a deficient number, since it is larger than the sum of its proper divisors (820874339287).

114101533141433 is an equidigital number, since it uses as much as digits as its factorization.

114101533141433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 820874339286.

The product of its (nonzero) digits is 25920, while the sum is 35.

Adding to 114101533141433 its reverse (334141335101411), we get a palindrome (448242868242844).

The spelling of 114101533141433 in words is "one hundred fourteen trillion, one hundred one billion, five hundred thirty-three million, one hundred forty-one thousand, four hundred thirty-three".