Base | Representation |
---|---|
bin | 10101010000001110… |
… | …10000101101001001 |
3 | 1002110012200220100101 |
4 | 22220013100231021 |
5 | 141332031112223 |
6 | 5124124405401 |
7 | 552521613241 |
oct | 125007205511 |
9 | 32405626311 |
10 | 11410410313 |
11 | 4925974175 |
12 | 22653a6861 |
13 | 10cac724a3 |
14 | 7a35c4b21 |
15 | 46bb0c4ad |
hex | 2a81d0b49 |
11410410313 has 2 divisors, whose sum is σ = 11410410314. Its totient is φ = 11410410312.
The previous prime is 11410410307. The next prime is 11410410329. The reversal of 11410410313 is 31301401411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9790508809 + 1619901504 = 98947^2 + 40248^2 .
It is a cyclic number.
It is not a de Polignac number, because 11410410313 - 217 = 11410279241 is a prime.
It is a super-2 number, since 2×114104103132 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11410410113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705205156 + 5705205157.
It is an arithmetic number, because the mean of its divisors is an integer number (5705205157).
Almost surely, 211410410313 is an apocalyptic number.
It is an amenable number.
11410410313 is a deficient number, since it is larger than the sum of its proper divisors (1).
11410410313 is an equidigital number, since it uses as much as digits as its factorization.
11410410313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 11410410313 its reverse (31301401411), we get a palindrome (42711811724).
The spelling of 11410410313 in words is "eleven billion, four hundred ten million, four hundred ten thousand, three hundred thirteen".
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