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11410410313 is a prime number
BaseRepresentation
bin10101010000001110…
…10000101101001001
31002110012200220100101
422220013100231021
5141332031112223
65124124405401
7552521613241
oct125007205511
932405626311
1011410410313
114925974175
1222653a6861
1310cac724a3
147a35c4b21
1546bb0c4ad
hex2a81d0b49

11410410313 has 2 divisors, whose sum is σ = 11410410314. Its totient is φ = 11410410312.

The previous prime is 11410410307. The next prime is 11410410329. The reversal of 11410410313 is 31301401411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9790508809 + 1619901504 = 98947^2 + 40248^2 .

It is a cyclic number.

It is not a de Polignac number, because 11410410313 - 217 = 11410279241 is a prime.

It is a super-2 number, since 2×114104103132 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11410410113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705205156 + 5705205157.

It is an arithmetic number, because the mean of its divisors is an integer number (5705205157).

Almost surely, 211410410313 is an apocalyptic number.

It is an amenable number.

11410410313 is a deficient number, since it is larger than the sum of its proper divisors (1).

11410410313 is an equidigital number, since it uses as much as digits as its factorization.

11410410313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11410410313 its reverse (31301401411), we get a palindrome (42711811724).

The spelling of 11410410313 in words is "eleven billion, four hundred ten million, four hundred ten thousand, three hundred thirteen".