Base | Representation |
---|---|
bin | 11001111100100001100101… |
… | …111000110110111100000011 |
3 | 112222000211220000022012002211 |
4 | 121330201211320312330003 |
5 | 104424041100013232120 |
6 | 1042405332212122551 |
7 | 33015130046506666 |
oct | 3174414570667403 |
9 | 488024800265084 |
10 | 114110400524035 |
11 | 333a4a49275573 |
12 | 1096b43a306457 |
13 | 4b8974555ca56 |
14 | 2026d897236dd |
15 | d2d417a2e25a |
hex | 67c865e36f03 |
114110400524035 has 16 divisors (see below), whose sum is σ = 140204694950496. Its totient is φ = 89109502933248.
The previous prime is 114110400524023. The next prime is 114110400524041. The reversal of 114110400524035 is 530425004011411.
It is a cyclic number.
It is not a de Polignac number, because 114110400524035 - 29 = 114110400523523 is a prime.
It is a super-2 number, since 2×1141104005240352 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 114110400523988 and 114110400524006.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 165826354 + ... + 166513063.
It is an arithmetic number, because the mean of its divisors is an integer number (8762793434406).
Almost surely, 2114110400524035 is an apocalyptic number.
114110400524035 is a deficient number, since it is larger than the sum of its proper divisors (26094294426461).
114110400524035 is a wasteful number, since it uses less digits than its factorization.
114110400524035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 332341062.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 114110400524035 its reverse (530425004011411), we get a palindrome (644535404535446).
The spelling of 114110400524035 in words is "one hundred fourteen trillion, one hundred ten billion, four hundred million, five hundred twenty-four thousand, thirty-five".
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