Base | Representation |
---|---|
bin | 1010011000001101110100… |
… | …1101011101001000000011 |
3 | 1111101220011021102202100222 |
4 | 2212003131031131020003 |
5 | 2443430010433230313 |
6 | 40134112443333255 |
7 | 2255266540161206 |
oct | 246033515351003 |
9 | 44356137382328 |
10 | 11411144430083 |
11 | 36aa4915a7602 |
12 | 134368122122b |
13 | 64a0b2888608 |
14 | 2b643388393d |
15 | 14bc6b671208 |
hex | a60dd35d203 |
11411144430083 has 2 divisors, whose sum is σ = 11411144430084. Its totient is φ = 11411144430082.
The previous prime is 11411144430013. The next prime is 11411144430131. The reversal of 11411144430083 is 38003444111411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11411144430083 - 242 = 7013097918979 is a prime.
It is not a weakly prime, because it can be changed into another prime (11411144430013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705572215041 + 5705572215042.
It is an arithmetic number, because the mean of its divisors is an integer number (5705572215042).
Almost surely, 211411144430083 is an apocalyptic number.
11411144430083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11411144430083 is an equidigital number, since it uses as much as digits as its factorization.
11411144430083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18432, while the sum is 35.
Adding to 11411144430083 its reverse (38003444111411), we get a palindrome (49414588541494).
The spelling of 11411144430083 in words is "eleven trillion, four hundred eleven billion, one hundred forty-four million, four hundred thirty thousand, eighty-three".
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