Base | Representation |
---|---|
bin | 10000100110110000000… |
… | …011110001110101010011 |
3 | 11001002102121210222210001 |
4 | 100212300003301311103 |
5 | 122144003222122003 |
6 | 2232120124150431 |
7 | 145305006633562 |
oct | 20466003616523 |
9 | 4032377728701 |
10 | 1141120114003 |
11 | 3aaa45612291 |
12 | 1651a6998417 |
13 | 837b7c3178c |
14 | 3d33272bbd9 |
15 | 1ea3a99361d |
hex | 109b00f1d53 |
1141120114003 has 2 divisors, whose sum is σ = 1141120114004. Its totient is φ = 1141120114002.
The previous prime is 1141120113983. The next prime is 1141120114033. The reversal of 1141120114003 is 3004110211411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1141120114003 - 25 = 1141120113971 is a prime.
It is a super-2 number, since 2×11411201140032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1141120114033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570560057001 + 570560057002.
It is an arithmetic number, because the mean of its divisors is an integer number (570560057002).
Almost surely, 21141120114003 is an apocalyptic number.
1141120114003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141120114003 is an equidigital number, since it uses as much as digits as its factorization.
1141120114003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 1141120114003 its reverse (3004110211411), we get a palindrome (4145230325414).
The spelling of 1141120114003 in words is "one trillion, one hundred forty-one billion, one hundred twenty million, one hundred fourteen thousand, three".
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