Base | Representation |
---|---|
bin | 110101001000110100… |
… | …0011110000110000011 |
3 | 101220112200201100010211 |
4 | 1222101220132012003 |
5 | 3332200242030133 |
6 | 124231133534551 |
7 | 11146545602206 |
oct | 1522150360603 |
9 | 356480640124 |
10 | 114112455043 |
11 | 44438562494 |
12 | 1a148044457 |
13 | a9b7503262 |
14 | 574744b93d |
15 | 2e7d182bcd |
hex | 1a91a1e183 |
114112455043 has 2 divisors, whose sum is σ = 114112455044. Its totient is φ = 114112455042.
The previous prime is 114112455031. The next prime is 114112455179. The reversal of 114112455043 is 340554211411.
It is a weak prime.
It is an emirp because it is prime and its reverse (340554211411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114112455043 - 25 = 114112455011 is a prime.
It is a super-2 number, since 2×1141124550432 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114112454996 and 114112455014.
It is not a weakly prime, because it can be changed into another prime (114112458043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57056227521 + 57056227522.
It is an arithmetic number, because the mean of its divisors is an integer number (57056227522).
Almost surely, 2114112455043 is an apocalyptic number.
114112455043 is a deficient number, since it is larger than the sum of its proper divisors (1).
114112455043 is an equidigital number, since it uses as much as digits as its factorization.
114112455043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 114112455043 its reverse (340554211411), we get a palindrome (454666666454).
The spelling of 114112455043 in words is "one hundred fourteen billion, one hundred twelve million, four hundred fifty-five thousand, forty-three".
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