Base | Representation |
---|---|
bin | 110101001000110100… |
… | …0101001001101001001 |
3 | 101220112200210122120101 |
4 | 1222101220221031021 |
5 | 3332200300004203 |
6 | 124231134525401 |
7 | 11146546151662 |
oct | 1522150511511 |
9 | 356480718511 |
10 | 114112500553 |
11 | 444385936a7 |
12 | 1a148066861 |
13 | a9b751ab9c |
14 | 5747460369 |
15 | 2e7d19141d |
hex | 1a91a29349 |
114112500553 has 2 divisors, whose sum is σ = 114112500554. Its totient is φ = 114112500552.
The previous prime is 114112500511. The next prime is 114112500571. The reversal of 114112500553 is 355005211411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 110684632249 + 3427868304 = 332693^2 + 58548^2 .
It is a cyclic number.
It is not a de Polignac number, because 114112500553 - 229 = 113575629641 is a prime.
It is not a weakly prime, because it can be changed into another prime (114112500583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57056250276 + 57056250277.
It is an arithmetic number, because the mean of its divisors is an integer number (57056250277).
Almost surely, 2114112500553 is an apocalyptic number.
It is an amenable number.
114112500553 is a deficient number, since it is larger than the sum of its proper divisors (1).
114112500553 is an equidigital number, since it uses as much as digits as its factorization.
114112500553 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3000, while the sum is 28.
Adding to 114112500553 its reverse (355005211411), we get a palindrome (469117711964).
The spelling of 114112500553 in words is "one hundred fourteen billion, one hundred twelve million, five hundred thousand, five hundred fifty-three".
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