Search a number
-
+
11411255414353 = 17053669164101
BaseRepresentation
bin1010011000001110001111…
…0100110100111001010001
31111101220110000021100011111
42212003203310310321101
52443430222341224403
640134131450213321
72255302355422414
oct246034364647121
944356400240144
1011411255414353
1136aa539210743
1213436b2424241
1364a0cc876992
142b64444d3b7b
1514bc7629556d
hexa60e3d34e51

11411255414353 has 4 divisors (see below), whose sum is σ = 11411924595508. Its totient is φ = 11410586233200.

The previous prime is 11411255414249. The next prime is 11411255414359. The reversal of 11411255414353 is 35341455211411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4593036200769 + 6818219213584 = 2143137^2 + 2611172^2 .

It is a cyclic number.

It is not a de Polignac number, because 11411255414353 - 221 = 11411253317201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11411255414359) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 334564998 + ... + 334599103.

It is an arithmetic number, because the mean of its divisors is an integer number (2852981148877).

Almost surely, 211411255414353 is an apocalyptic number.

It is an amenable number.

11411255414353 is a deficient number, since it is larger than the sum of its proper divisors (669181155).

11411255414353 is an equidigital number, since it uses as much as digits as its factorization.

11411255414353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 669181154.

The product of its digits is 144000, while the sum is 40.

The spelling of 11411255414353 in words is "eleven trillion, four hundred eleven billion, two hundred fifty-five million, four hundred fourteen thousand, three hundred fifty-three".

Divisors: 1 17053 669164101 11411255414353