Search a number
-
+
114113003483 is a prime number
BaseRepresentation
bin110101001000110101…
…0100011111111011011
3101220112201202012110102
41222101222203333123
53332200412102413
6124231153410015
711146553345153
oct1522152437733
9356481665412
10114113003483
11444388a7546
121a14826990b
13a9b7665a8b
145747551763
152e7d240458
hex1a91aa3fdb

114113003483 has 2 divisors, whose sum is σ = 114113003484. Its totient is φ = 114113003482.

The previous prime is 114113003443. The next prime is 114113003491. The reversal of 114113003483 is 384300311411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 114113003483 - 28 = 114113003227 is a prime.

It is a super-2 number, since 2×1141130034832 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (114113003443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57056501741 + 57056501742.

It is an arithmetic number, because the mean of its divisors is an integer number (57056501742).

Almost surely, 2114113003483 is an apocalyptic number.

114113003483 is a deficient number, since it is larger than the sum of its proper divisors (1).

114113003483 is an equidigital number, since it uses as much as digits as its factorization.

114113003483 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 114113003483 its reverse (384300311411), we get a palindrome (498413314894).

The spelling of 114113003483 in words is "one hundred fourteen billion, one hundred thirteen million, three thousand, four hundred eighty-three".