Base | Representation |
---|---|
bin | 110101001000110101… |
… | …1101101001001101011 |
3 | 101220112202022102112002 |
4 | 1222101223231021223 |
5 | 3332201001200042 |
6 | 124231204041215 |
7 | 11146556033624 |
oct | 1522153551153 |
9 | 356482272462 |
10 | 114113303147 |
11 | 44438a916a8 |
12 | 1a14839320b |
13 | a9b773c2ac |
14 | 57475cca4b |
15 | 2e7d29e132 |
hex | 1a91aed26b |
114113303147 has 2 divisors, whose sum is σ = 114113303148. Its totient is φ = 114113303146.
The previous prime is 114113303119. The next prime is 114113303153. The reversal of 114113303147 is 741303311411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114113303147 - 222 = 114109108843 is a prime.
It is not a weakly prime, because it can be changed into another prime (114113383147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57056651573 + 57056651574.
It is an arithmetic number, because the mean of its divisors is an integer number (57056651574).
Almost surely, 2114113303147 is an apocalyptic number.
114113303147 is a deficient number, since it is larger than the sum of its proper divisors (1).
114113303147 is an equidigital number, since it uses as much as digits as its factorization.
114113303147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 29.
Adding to 114113303147 its reverse (741303311411), we get a palindrome (855416614558).
The spelling of 114113303147 in words is "one hundred fourteen billion, one hundred thirteen million, three hundred three thousand, one hundred forty-seven".
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