Base | Representation |
---|---|
bin | 11001111100100101111000… |
… | …000011011011001101100011 |
3 | 112222001021202120111112121111 |
4 | 121330211320003123031203 |
5 | 104424130010031014420 |
6 | 1042411412444204151 |
7 | 33015352041525244 |
oct | 3174457003331543 |
9 | 488037676445544 |
10 | 114115000251235 |
11 | 333a6999740705 |
12 | 10970302839657 |
13 | 4b89cc94b2b19 |
14 | 20272a458cccb |
15 | d2d5d676b45a |
hex | 67c9780db363 |
114115000251235 has 16 divisors (see below), whose sum is σ = 141050569271040. Its totient is φ = 88578407685600.
The previous prime is 114115000251209. The next prime is 114115000251271. The reversal of 114115000251235 is 532152000511411.
It is not a de Polignac number, because 114115000251235 - 29 = 114115000250723 is a prime.
It is a super-2 number, since 2×1141150002512352 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114115000251197 and 114115000251206.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1757475625 + ... + 1757540554.
It is an arithmetic number, because the mean of its divisors is an integer number (8815660579440).
Almost surely, 2114115000251235 is an apocalyptic number.
114115000251235 is a deficient number, since it is larger than the sum of its proper divisors (26935569019805).
114115000251235 is a wasteful number, since it uses less digits than its factorization.
114115000251235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3515016378.
The product of its (nonzero) digits is 6000, while the sum is 31.
Adding to 114115000251235 its reverse (532152000511411), we get a palindrome (646267000762646).
The spelling of 114115000251235 in words is "one hundred fourteen trillion, one hundred fifteen billion, two hundred fifty-one thousand, two hundred thirty-five".
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