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114115103353 = 253145086963
BaseRepresentation
bin110101001000111001…
…0100100101001111001
3101220112212200212221101
41222101302210221321
53332201431301403
6124231310411401
711146610242216
oct1522162445171
9356485625841
10114115103353
114443a001179
121a148b00b61
13a9b7c1c7c4
14574793ab0d
152e7d50771d
hex1a91ca4a79

114115103353 has 4 divisors (see below), whose sum is σ = 114160192848. Its totient is φ = 114070013860.

The previous prime is 114115103303. The next prime is 114115103357. The reversal of 114115103353 is 353301511411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 353301511411 = 1948091813579.

It is a cyclic number.

It is not a de Polignac number, because 114115103353 - 213 = 114115095161 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114115103357) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22540951 + ... + 22546012.

It is an arithmetic number, because the mean of its divisors is an integer number (28540048212).

Almost surely, 2114115103353 is an apocalyptic number.

It is an amenable number.

114115103353 is a deficient number, since it is larger than the sum of its proper divisors (45089495).

114115103353 is an equidigital number, since it uses as much as digits as its factorization.

114115103353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45089494.

The product of its (nonzero) digits is 2700, while the sum is 28.

Adding to 114115103353 its reverse (353301511411), we get a palindrome (467416614764).

The spelling of 114115103353 in words is "one hundred fourteen billion, one hundred fifteen million, one hundred three thousand, three hundred fifty-three".

Divisors: 1 2531 45086963 114115103353