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1141204153 is a prime number
BaseRepresentation
bin100010000000101…
…0110010010111001
32221112101011210111
41010001112102321
54314122013103
6305123544321
740165034545
oct10401262271
92845334714
101141204153
115361a8631
1227a22b0a1
1315257963b
14ab7c6a25
156a2c486d
hex440564b9

1141204153 has 2 divisors, whose sum is σ = 1141204154. Its totient is φ = 1141204152.

The previous prime is 1141204111. The next prime is 1141204159. The reversal of 1141204153 is 3514021411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1129833769 + 11370384 = 33613^2 + 3372^2 .

It is a cyclic number.

It is not a de Polignac number, because 1141204153 - 213 = 1141195961 is a prime.

It is not a weakly prime, because it can be changed into another prime (1141204159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570602076 + 570602077.

It is an arithmetic number, because the mean of its divisors is an integer number (570602077).

Almost surely, 21141204153 is an apocalyptic number.

It is an amenable number.

1141204153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141204153 is an equidigital number, since it uses as much as digits as its factorization.

1141204153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 480, while the sum is 22.

The square root of 1141204153 is about 33781.7132928453. The cubic root of 1141204153 is about 1045.0116076639.

Adding to 1141204153 its reverse (3514021411), we get a palindrome (4655225564).

The spelling of 1141204153 in words is "one billion, one hundred forty-one million, two hundred four thousand, one hundred fifty-three".