Base | Representation |
---|---|
bin | 10101010000011100… |
… | …00100100101011001 |
3 | 1002110100001121101211 |
4 | 22220032010211121 |
5 | 141333010230143 |
6 | 5124230543121 |
7 | 552543030334 |
oct | 125016044531 |
9 | 32410047354 |
10 | 11412195673 |
11 | 492698357a |
12 | 2265b07aa1 |
13 | 10cb449008 |
14 | 7a392b61b |
15 | 46bd6149d |
hex | 2a8384959 |
11412195673 has 2 divisors, whose sum is σ = 11412195674. Its totient is φ = 11412195672.
The previous prime is 11412195661. The next prime is 11412195679. The reversal of 11412195673 is 37659121411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6632962249 + 4779233424 = 81443^2 + 69132^2 .
It is an emirp because it is prime and its reverse (37659121411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11412195673 - 213 = 11412187481 is a prime.
It is not a weakly prime, because it can be changed into another prime (11412195679) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706097836 + 5706097837.
It is an arithmetic number, because the mean of its divisors is an integer number (5706097837).
Almost surely, 211412195673 is an apocalyptic number.
It is an amenable number.
11412195673 is a deficient number, since it is larger than the sum of its proper divisors (1).
11412195673 is an equidigital number, since it uses as much as digits as its factorization.
11412195673 is an evil number, because the sum of its binary digits is even.
The product of its digits is 45360, while the sum is 40.
The spelling of 11412195673 in words is "eleven billion, four hundred twelve million, one hundred ninety-five thousand, six hundred seventy-three".
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