Base | Representation |
---|---|
bin | 110101001001001001… |
… | …0101001011001111001 |
3 | 101220120110112001122011 |
4 | 1222102102221121321 |
5 | 3332211104331132 |
6 | 124232210525521 |
7 | 11150041561426 |
oct | 1522222513171 |
9 | 356513461564 |
10 | 114123511417 |
11 | 44443824293 |
12 | 1a14b8968a1 |
13 | a9b98a48a6 |
14 | 5748ac8d4d |
15 | 2e7e118b47 |
hex | 1a924a9679 |
114123511417 has 2 divisors, whose sum is σ = 114123511418. Its totient is φ = 114123511416.
The previous prime is 114123511373. The next prime is 114123511421. The reversal of 114123511417 is 714115321411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 64953109881 + 49170401536 = 254859^2 + 221744^2 .
It is a cyclic number.
It is not a de Polignac number, because 114123511417 - 27 = 114123511289 is a prime.
It is a super-2 number, since 2×1141235114172 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (114123511517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57061755708 + 57061755709.
It is an arithmetic number, because the mean of its divisors is an integer number (57061755709).
Almost surely, 2114123511417 is an apocalyptic number.
It is an amenable number.
114123511417 is a deficient number, since it is larger than the sum of its proper divisors (1).
114123511417 is an equidigital number, since it uses as much as digits as its factorization.
114123511417 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3360, while the sum is 31.
Adding to 114123511417 its reverse (714115321411), we get a palindrome (828238832828).
The spelling of 114123511417 in words is "one hundred fourteen billion, one hundred twenty-three million, five hundred eleven thousand, four hundred seventeen".
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