Base | Representation |
---|---|
bin | 10101010000011101… |
… | …10001111101110001 |
3 | 1002110100102001101021 |
4 | 22220032301331301 |
5 | 141333032202203 |
6 | 5124234535441 |
7 | 552544433266 |
oct | 125016617561 |
9 | 32410361337 |
10 | 11412381553 |
11 | 4926aa01a1 |
12 | 2265b97581 |
13 | 10cb4b27c1 |
14 | 7a397926d |
15 | 46bd9b5bd |
hex | 2a83b1f71 |
11412381553 has 2 divisors, whose sum is σ = 11412381554. Its totient is φ = 11412381552.
The previous prime is 11412381493. The next prime is 11412381557. The reversal of 11412381553 is 35518321411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7339006224 + 4073375329 = 85668^2 + 63823^2 .
It is an emirp because it is prime and its reverse (35518321411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11412381553 - 29 = 11412381041 is a prime.
It is a super-2 number, since 2×114123815532 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11412381557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706190776 + 5706190777.
It is an arithmetic number, because the mean of its divisors is an integer number (5706190777).
Almost surely, 211412381553 is an apocalyptic number.
It is an amenable number.
11412381553 is a deficient number, since it is larger than the sum of its proper divisors (1).
11412381553 is an equidigital number, since it uses as much as digits as its factorization.
11412381553 is an evil number, because the sum of its binary digits is even.
The product of its digits is 14400, while the sum is 34.
The spelling of 11412381553 in words is "eleven billion, four hundred twelve million, three hundred eighty-one thousand, five hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •