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11412381553 is a prime number
BaseRepresentation
bin10101010000011101…
…10001111101110001
31002110100102001101021
422220032301331301
5141333032202203
65124234535441
7552544433266
oct125016617561
932410361337
1011412381553
114926aa01a1
122265b97581
1310cb4b27c1
147a397926d
1546bd9b5bd
hex2a83b1f71

11412381553 has 2 divisors, whose sum is σ = 11412381554. Its totient is φ = 11412381552.

The previous prime is 11412381493. The next prime is 11412381557. The reversal of 11412381553 is 35518321411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7339006224 + 4073375329 = 85668^2 + 63823^2 .

It is an emirp because it is prime and its reverse (35518321411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11412381553 - 29 = 11412381041 is a prime.

It is a super-2 number, since 2×114123815532 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11412381557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706190776 + 5706190777.

It is an arithmetic number, because the mean of its divisors is an integer number (5706190777).

Almost surely, 211412381553 is an apocalyptic number.

It is an amenable number.

11412381553 is a deficient number, since it is larger than the sum of its proper divisors (1).

11412381553 is an equidigital number, since it uses as much as digits as its factorization.

11412381553 is an evil number, because the sum of its binary digits is even.

The product of its digits is 14400, while the sum is 34.

The spelling of 11412381553 in words is "eleven billion, four hundred twelve million, three hundred eighty-one thousand, five hundred fifty-three".