Base | Representation |
---|---|
bin | 10000100110111000000… |
… | …010110101100000101010 |
3 | 11001002202221220101221212 |
4 | 100212320002311200222 |
5 | 122144242021202100 |
6 | 2232141311433122 |
7 | 145311224442551 |
oct | 20467002654052 |
9 | 4032687811855 |
10 | 1141254084650 |
11 | 4000041a6429 |
12 | 1652238257a2 |
13 | 8380990a654 |
14 | 3d346442d98 |
15 | 1ea47608635 |
hex | 109b80b582a |
1141254084650 has 12 divisors (see below), whose sum is σ = 2122732597542. Its totient is φ = 456501633840.
The previous prime is 1141254084631. The next prime is 1141254084671. The reversal of 1141254084650 is 564804521411.
It can be written as a sum of positive squares in 3 ways, for example, as 825901081681 + 315353002969 = 908791^2 + 561563^2 .
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1141254084598 and 1141254084607.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 11412540797 + ... + 11412540896.
Almost surely, 21141254084650 is an apocalyptic number.
1141254084650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1141254084650 is a deficient number, since it is larger than the sum of its proper divisors (981478512892).
1141254084650 is a wasteful number, since it uses less digits than its factorization.
1141254084650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22825081705 (or 22825081700 counting only the distinct ones).
The product of its (nonzero) digits is 153600, while the sum is 41.
The spelling of 1141254084650 in words is "one trillion, one hundred forty-one billion, two hundred fifty-four million, eighty-four thousand, six hundred fifty".
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