114130240011331 has 4 divisors (see below), whose sum is σ = 114170469214032. Its totient is φ = 114090010808632.

The previous prime is 114130240011269. The next prime is 114130240011481. The reversal of 114130240011331 is 133110042031411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114130240011331 - 2³⁷ = 113992801057859 is a prime.

It is a super-3 number, since 3×114130240011331³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114130240011296 and 114130240011305.

It is not an unprimeable number, because it can be changed into a prime (114130240011031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20114597095 + ... + 20114602768.

It is an arithmetic number, because the mean of its divisors is an integer number (28542617303508).

Almost surely, 2^{114130240011331} is an apocalyptic number.

114130240011331 is a deficient number, since it is larger than the sum of its proper divisors (40229202701).

114130240011331 is an equidigital number, since it uses as much as digits as its factorization.

114130240011331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40229202700.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 114130240011331 its reverse (133110042031411), we get a palindrome (247240282042742).

The spelling of 114130240011331 in words is "one hundred fourteen trillion, one hundred thirty billion, two hundred forty million, eleven thousand, three hundred thirty-one".