Base | Representation |
---|---|
bin | 1010011000010100111011… |
… | …0111011001011100001100 |
3 | 1111102002002011110021011022 |
4 | 2212011032313121130030 |
5 | 2443442412110003234 |
6 | 40135030001213312 |
7 | 2255365022655224 |
oct | 246051667313414 |
9 | 44362064407138 |
10 | 11413051250444 |
11 | 370027a9909a8 |
12 | 1343b13931238 |
13 | 64a32793969c |
14 | 2b6574c05084 |
15 | 14bd2dc79e2e |
hex | a614edd970c |
11413051250444 has 12 divisors (see below), whose sum is σ = 19974765967800. Its totient is φ = 5705975259648.
The previous prime is 11413051250431. The next prime is 11413051250449. The reversal of 11413051250444 is 44405215031411.
11413051250444 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×114130512504442 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11413051250449) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 137544734 + ... + 137627685.
It is an arithmetic number, because the mean of its divisors is an integer number (1664563830650).
Almost surely, 211413051250444 is an apocalyptic number.
It is an amenable number.
11413051250444 is a deficient number, since it is larger than the sum of its proper divisors (8561714717356).
11413051250444 is a wasteful number, since it uses less digits than its factorization.
11413051250444 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 275182792 (or 275182790 counting only the distinct ones).
The product of its (nonzero) digits is 38400, while the sum is 35.
Adding to 11413051250444 its reverse (44405215031411), we get a palindrome (55818266281855).
The spelling of 11413051250444 in words is "eleven trillion, four hundred thirteen billion, fifty-one million, two hundred fifty thousand, four hundred forty-four".
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