Base | Representation |
---|---|
bin | 11001111100110100100001… |
… | …101100011101100011110001 |
3 | 112222002210100220011121000010 |
4 | 121330310201230131203301 |
5 | 104424404214200311040 |
6 | 1042422533434245133 |
7 | 33016446626066055 |
oct | 3174644154354361 |
9 | 488083326147003 |
10 | 114130731260145 |
11 | 33402631461516 |
12 | 10973372b867a9 |
13 | 4b8b635607512 |
14 | 2027d578ddc65 |
15 | d2dc0782ae80 |
hex | 67cd21b1d8f1 |
114130731260145 has 16 divisors (see below), whose sum is σ = 183922905055680. Its totient is φ = 60431811658944.
The previous prime is 114130731260087. The next prime is 114130731260167. The reversal of 114130731260145 is 541062137031411.
It is not a de Polignac number, because 114130731260145 - 26 = 114130731260081 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27369477834 + ... + 27369482003.
It is an arithmetic number, because the mean of its divisors is an integer number (11495181565980).
Almost surely, 2114130731260145 is an apocalyptic number.
114130731260145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
114130731260145 is a deficient number, since it is larger than the sum of its proper divisors (69792173795535).
114130731260145 is a wasteful number, since it uses less digits than its factorization.
114130731260145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54738959984.
The product of its (nonzero) digits is 60480, while the sum is 39.
Adding to 114130731260145 its reverse (541062137031411), we get a palindrome (655192868291556).
The spelling of 114130731260145 in words is "one hundred fourteen trillion, one hundred thirty billion, seven hundred thirty-one million, two hundred sixty thousand, one hundred forty-five".
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