1141321446113 has 2 divisors, whose sum is σ = 1141321446114. Its totient is φ = 1141321446112.

The previous prime is 1141321446077. The next prime is 1141321446119. The reversal of 1141321446113 is 3116441231411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1111795209889 + 29526236224 = 1054417^2 + 171832^2 .

It is a cyclic number.

It is not a de Polignac number, because 1141321446113 - 2¹² = 1141321442017 is a prime.

It is a super-2 number, since 2×1141321446113² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1141321446113.

It is not a weakly prime, because it can be changed into another prime (1141321446119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570660723056 + 570660723057.

It is an arithmetic number, because the mean of its divisors is an integer number (570660723057).

Almost surely, 2^{1141321446113} is an apocalyptic number.

It is an amenable number.

1141321446113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141321446113 is an equidigital number, since it uses as much as digits as its factorization.

1141321446113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6912, while the sum is 32.

Adding to 1141321446113 its reverse (3116441231411), we get a palindrome (4257762677524).

The spelling of 1141321446113 in words is "one trillion, one hundred forty-one billion, three hundred twenty-one million, four hundred forty-six thousand, one hundred thirteen".