Base | Representation |
---|---|
bin | 10000100110111100110… |
… | …001100011011011000001 |
3 | 11001002222111020002022001 |
4 | 100212330301203123001 |
5 | 122144422330041233 |
6 | 2232153224344001 |
7 | 145313210113042 |
oct | 20467461433301 |
9 | 4032874202261 |
10 | 1141333440193 |
11 | 400044a77421 |
12 | 165246315001 |
13 | 838201a35ab |
14 | 3d352bbc8c9 |
15 | 1ea4e58127d |
hex | 109bcc636c1 |
1141333440193 has 2 divisors, whose sum is σ = 1141333440194. Its totient is φ = 1141333440192.
The previous prime is 1141333440131. The next prime is 1141333440211. The reversal of 1141333440193 is 3910443331411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1120669952689 + 20663487504 = 1058617^2 + 143748^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1141333440193 is a prime.
It is not a weakly prime, because it can be changed into another prime (1141333440113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570666720096 + 570666720097.
It is an arithmetic number, because the mean of its divisors is an integer number (570666720097).
Almost surely, 21141333440193 is an apocalyptic number.
It is an amenable number.
1141333440193 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141333440193 is an equidigital number, since it uses as much as digits as its factorization.
1141333440193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46656, while the sum is 37.
The spelling of 1141333440193 in words is "one trillion, one hundred forty-one billion, three hundred thirty-three million, four hundred forty thousand, one hundred ninety-three".
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