114133400233 has 2 divisors, whose sum is σ = 114133400234. Its totient is φ = 114133400232.

The previous prime is 114133400221. The next prime is 114133400237. The reversal of 114133400233 is 332004331411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110149644544 + 3983755689 = 331888^2 + 63117^2 .

It is an emirp because it is prime and its reverse (332004331411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114133400233 - 2¹³ = 114133392041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114133400198 and 114133400207.

It is not a weakly prime, because it can be changed into another prime (114133400237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57066700116 + 57066700117.

It is an arithmetic number, because the mean of its divisors is an integer number (57066700117).

Almost surely, 2^114133400233 is an apocalyptic number.

It is an amenable number.

114133400233 is a deficient number, since it is larger than the sum of its proper divisors (1).

114133400233 is an equidigital number, since it uses as much as digits as its factorization.

114133400233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 114133400233 its reverse (332004331411), we get a palindrome (446137731644).

The spelling of 114133400233 in words is "one hundred fourteen billion, one hundred thirty-three million, four hundred thousand, two hundred thirty-three".