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114134210233 is a prime number
BaseRepresentation
bin110101001001011101…
…1011101011010111001
3101220121012122121122121
41222102323131122321
53332221324211413
6124233232121241
711150231531341
oct1522273353271
9356535577577
10114134210233
114444987148a
121a153396221
13a9bbb7c554
14574a2b1d21
152e8002db8d
hex1a92edd6b9

114134210233 has 2 divisors, whose sum is σ = 114134210234. Its totient is φ = 114134210232.

The previous prime is 114134210191. The next prime is 114134210249. The reversal of 114134210233 is 332012431411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112528044304 + 1606165929 = 335452^2 + 40077^2 .

It is an emirp because it is prime and its reverse (332012431411) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114134210233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114134210198 and 114134210207.

It is not a weakly prime, because it can be changed into another prime (114134216233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57067105116 + 57067105117.

It is an arithmetic number, because the mean of its divisors is an integer number (57067105117).

Almost surely, 2114134210233 is an apocalyptic number.

It is an amenable number.

114134210233 is a deficient number, since it is larger than the sum of its proper divisors (1).

114134210233 is an equidigital number, since it uses as much as digits as its factorization.

114134210233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 114134210233 its reverse (332012431411), we get a palindrome (446146641644).

The spelling of 114134210233 in words is "one hundred fourteen billion, one hundred thirty-four million, two hundred ten thousand, two hundred thirty-three".