11413433113 has 4 divisors (see below), whose sum is σ = 11417731380. Its totient is φ = 11409134848.

The previous prime is 11413433081. The next prime is 11413433131. The reversal of 11413433113 is 31133431411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31133431411 = 167 ⋅186427733.

It can be written as a sum of positive squares in 2 ways, for example, as 4848058384 + 6565374729 = 69628^2 + 81027^2 .

It is a cyclic number.

It is not a de Polignac number, because 11413433113 - 2⁵ = 11413433081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11413433413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2145148 + ... + 2150461.

It is an arithmetic number, because the mean of its divisors is an integer number (2854432845).

Almost surely, 2^11413433113 is an apocalyptic number.

It is an amenable number.

11413433113 is a deficient number, since it is larger than the sum of its proper divisors (4298267).

11413433113 is an equidigital number, since it uses as much as digits as its factorization.

11413433113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4298266.

The product of its digits is 1296, while the sum is 25.

Adding to 11413433113 its reverse (31133431411), we get a palindrome (42546864524).

The spelling of 11413433113 in words is "eleven billion, four hundred thirteen million, four hundred thirty-three thousand, one hundred thirteen".