114134454113 has 4 divisors (see below), whose sum is σ = 114394441920. Its totient is φ = 113874466308.

The previous prime is 114134454097. The next prime is 114134454173. The reversal of 114134454113 is 311454431411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114134454113 - 2⁴ = 114134454097 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 114134454113.

It is not an unprimeable number, because it can be changed into a prime (114134454173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 129993245 + ... + 129994122.

It is an arithmetic number, because the mean of its divisors is an integer number (28598610480).

Almost surely, 2^114134454113 is an apocalyptic number.

It is an amenable number.

114134454113 is a deficient number, since it is larger than the sum of its proper divisors (259987807).

114134454113 is an equidigital number, since it uses as much as digits as its factorization.

114134454113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 259987806.

The product of its digits is 11520, while the sum is 32.

Adding to 114134454113 its reverse (311454431411), we get a palindrome (425588885524).

The spelling of 114134454113 in words is "one hundred fourteen billion, one hundred thirty-four million, four hundred fifty-four thousand, one hundred thirteen".