Base | Representation |
---|---|
bin | 10101010000100110… |
… | …11001101111011010 |
3 | 1002110102200121020112 |
4 | 22220103121233122 |
5 | 141333334434200 |
6 | 5124320524322 |
7 | 552560640326 |
oct | 125023315732 |
9 | 32412617215 |
10 | 11413593050 |
11 | 4927748432 |
12 | 22664806a2 |
13 | 10cb818072 |
14 | 7a3bb2986 |
15 | 46c03a535 |
hex | 2a84d9bda |
11413593050 has 12 divisors (see below), whose sum is σ = 21229283166. Its totient is φ = 4565437200.
The previous prime is 11413593043. The next prime is 11413593077. The reversal of 11413593050 is 5039531411.
It can be written as a sum of positive squares in 3 ways, for example, as 10750993969 + 662599081 = 103687^2 + 25741^2 .
It is a super-2 number, since 2×114135930502 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11413592998 and 11413593016.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 114135881 + ... + 114135980.
Almost surely, 211413593050 is an apocalyptic number.
11413593050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11413593050 is a deficient number, since it is larger than the sum of its proper divisors (9815690116).
11413593050 is a wasteful number, since it uses less digits than its factorization.
11413593050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 228271873 (or 228271868 counting only the distinct ones).
The product of its (nonzero) digits is 8100, while the sum is 32.
The spelling of 11413593050 in words is "eleven billion, four hundred thirteen million, five hundred ninety-three thousand, fifty".
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