Base | Representation |
---|---|
bin | 10000100110111110111… |
… | …000111111001111111001 |
3 | 11001010001222000211211101 |
4 | 100212332320333033321 |
5 | 122200010422143414 |
6 | 2232200533331401 |
7 | 145314120642406 |
oct | 20467670771771 |
9 | 4033058024741 |
10 | 1141368943609 |
11 | 400063016694 |
12 | 165256196b61 |
13 | 8382765452b |
14 | 3d3577c12ad |
15 | 1ea52745a74 |
hex | 109bee3f3f9 |
1141368943609 has 2 divisors, whose sum is σ = 1141368943610. Its totient is φ = 1141368943608.
The previous prime is 1141368943553. The next prime is 1141368943643. The reversal of 1141368943609 is 9063498631411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1136963701225 + 4405242384 = 1066285^2 + 66372^2 .
It is a cyclic number.
It is not a de Polignac number, because 1141368943609 - 29 = 1141368943097 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1141368943609.
It is not a weakly prime, because it can be changed into another prime (1141368944609) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570684471804 + 570684471805.
It is an arithmetic number, because the mean of its divisors is an integer number (570684471805).
Almost surely, 21141368943609 is an apocalyptic number.
It is an amenable number.
1141368943609 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141368943609 is an equidigital number, since it uses as much as digits as its factorization.
1141368943609 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3359232, while the sum is 55.
The spelling of 1141368943609 in words is "one trillion, one hundred forty-one billion, three hundred sixty-eight million, nine hundred forty-three thousand, six hundred nine".
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