11414003131 has 2 divisors, whose sum is σ = 11414003132. Its totient is φ = 11414003130.

The previous prime is 11414003089. The next prime is 11414003137. The reversal of 11414003131 is 13130041411.

It is a strong prime.

It is an emirp because it is prime and its reverse (13130041411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11414003131 - 2²³ = 11405614523 is a prime.

It is a super-2 number, since 2×11414003131² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11414003099 and 11414003108.

It is not a weakly prime, because it can be changed into another prime (11414003137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5707001565 + 5707001566.

It is an arithmetic number, because the mean of its divisors is an integer number (5707001566).

Almost surely, 2^11414003131 is an apocalyptic number.

11414003131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11414003131 is an equidigital number, since it uses as much as digits as its factorization.

11414003131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11414003131 its reverse (13130041411), we get a palindrome (24544044542).

The spelling of 11414003131 in words is "eleven billion, four hundred fourteen million, three thousand, one hundred thirty-one".