114140113 has 4 divisors (see below), whose sum is σ = 115187380. Its totient is φ = 113092848.

The previous prime is 114140029. The next prime is 114140119. The reversal of 114140113 is 311041411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311041411 = 701 ⋅443711.

It can be written as a sum of positive squares in 2 ways, for example, as 61968384 + 52171729 = 7872^2 + 7223^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114140113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114140119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 523470 + ... + 523687.

It is an arithmetic number, because the mean of its divisors is an integer number (28796845).

Almost surely, 2^114140113 is an apocalyptic number.

It is an amenable number.

114140113 is a deficient number, since it is larger than the sum of its proper divisors (1047267).

114140113 is a wasteful number, since it uses less digits than its factorization.

114140113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1047266.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 114140113 is about 10683.6376295717. The cubic root of 114140113 is about 485.0793266640.

Adding to 114140113 its reverse (311041411), we get a palindrome (425181524).

The spelling of 114140113 in words is "one hundred fourteen million, one hundred forty thousand, one hundred thirteen".