Base | Representation |
---|---|
bin | 10101010000101010… |
… | …11000111100100001 |
3 | 1002110110200001221222 |
4 | 22220111120330201 |
5 | 141334003122311 |
6 | 5124340024425 |
7 | 552565240346 |
oct | 125025307441 |
9 | 32413601858 |
10 | 11414114081 |
11 | 4927a73937 |
12 | 2266692115 |
13 | 10cb96b276 |
14 | 7a3caa7cd |
15 | 46c0deadb |
hex | 2a8558f21 |
11414114081 has 2 divisors, whose sum is σ = 11414114082. Its totient is φ = 11414114080.
The previous prime is 11414114069. The next prime is 11414114137. The reversal of 11414114081 is 18041141411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10629610000 + 784504081 = 103100^2 + 28009^2 .
It is a cyclic number.
It is not a de Polignac number, because 11414114081 - 210 = 11414113057 is a prime.
It is a super-2 number, since 2×114141140812 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11414114081.
It is not a weakly prime, because it can be changed into another prime (11414114051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5707057040 + 5707057041.
It is an arithmetic number, because the mean of its divisors is an integer number (5707057041).
Almost surely, 211414114081 is an apocalyptic number.
It is an amenable number.
11414114081 is a deficient number, since it is larger than the sum of its proper divisors (1).
11414114081 is an equidigital number, since it uses as much as digits as its factorization.
11414114081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 512, while the sum is 26.
Adding to 11414114081 its reverse (18041141411), we get a palindrome (29455255492).
The spelling of 11414114081 in words is "eleven billion, four hundred fourteen million, one hundred fourteen thousand, eighty-one".
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