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11414121 = 33804707
BaseRepresentation
bin101011100010…
…101001101001
3210110220020020
4223202221221
510410222441
61044351053
7166006215
oct53425151
923426206
1011414121
116496664
1239a5489
132498424
141731945
151006e66
hexae2a69

11414121 has 4 divisors (see below), whose sum is σ = 15218832. Its totient is φ = 7609412.

The previous prime is 11414119. The next prime is 11414129. The reversal of 11414121 is 12141411.

11414121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11414121 - 21 = 11414119 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11414121.

It is not an unprimeable number, because it can be changed into a prime (11414129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1902351 + ... + 1902356.

It is an arithmetic number, because the mean of its divisors is an integer number (3804708).

Almost surely, 211414121 is an apocalyptic number.

It is an amenable number.

11414121 is a deficient number, since it is larger than the sum of its proper divisors (3804711).

11414121 is an equidigital number, since it uses as much as digits as its factorization.

11414121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3804710.

The product of its digits is 32, while the sum is 15.

The square root of 11414121 is about 3378.4790956879. The cubic root of 11414121 is about 225.1545999212.

Adding to 11414121 its reverse (12141411), we get a palindrome (23555532).

The spelling of 11414121 in words is "eleven million, four hundred fourteen thousand, one hundred twenty-one".

Divisors: 1 3 3804707 11414121