Base | Representation |
---|---|
bin | 10000100111000001011… |
… | …110110110000101110011 |
3 | 11001010011222211202222021 |
4 | 100213001132312011303 |
5 | 122200103040001003 |
6 | 2232205125252311 |
7 | 145315156335520 |
oct | 20470136660563 |
9 | 4033158752867 |
10 | 1141412422003 |
11 | 400085612647 |
12 | 165268864097 |
13 | 838336683a9 |
14 | 3d35d49c147 |
15 | 1ea564832bd |
hex | 109c17b6173 |
1141412422003 has 4 divisors (see below), whose sum is σ = 1304471339440. Its totient is φ = 978353504568.
The previous prime is 1141412422001. The next prime is 1141412422037. The reversal of 1141412422003 is 3002242141411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1141412422003 - 21 = 1141412422001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1141412422001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81529458708 + ... + 81529458721.
It is an arithmetic number, because the mean of its divisors is an integer number (326117834860).
Almost surely, 21141412422003 is an apocalyptic number.
1141412422003 is a deficient number, since it is larger than the sum of its proper divisors (163058917437).
1141412422003 is an equidigital number, since it uses as much as digits as its factorization.
1141412422003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 163058917436.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 1141412422003 its reverse (3002242141411), we get a palindrome (4143654563414).
The spelling of 1141412422003 in words is "one trillion, one hundred forty-one billion, four hundred twelve million, four hundred twenty-two thousand, three".
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