114142001131 has 2 divisors, whose sum is σ = 114142001132. Its totient is φ = 114142001130.

The previous prime is 114142001111. The next prime is 114142001177. The reversal of 114142001131 is 131100241411.

It is a weak prime.

It is an emirp because it is prime and its reverse (131100241411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114142001131 - 2⁹ = 114142000619 is a prime.

It is a super-2 number, since 2×114142001131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114142001099 and 114142001108.

It is not a weakly prime, because it can be changed into another prime (114142001111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57071000565 + 57071000566.

It is an arithmetic number, because the mean of its divisors is an integer number (57071000566).

Almost surely, 2^114142001131 is an apocalyptic number.

114142001131 is a deficient number, since it is larger than the sum of its proper divisors (1).

114142001131 is an equidigital number, since it uses as much as digits as its factorization.

114142001131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 114142001131 its reverse (131100241411), we get a palindrome (245242242542).

The spelling of 114142001131 in words is "one hundred fourteen billion, one hundred forty-two million, one thousand, one hundred thirty-one".