Base | Representation |
---|---|
bin | 10000100111000010000… |
… | …100101001000001011011 |
3 | 11001010012200111011010011 |
4 | 100213002010221001123 |
5 | 122200113104024242 |
6 | 2232210121502351 |
7 | 145315336502614 |
oct | 20470204510133 |
9 | 4033180434104 |
10 | 1141422329947 |
11 | 40009016a629 |
12 | 1652700419b7 |
13 | 83835727093 |
14 | 3d36091ac0b |
15 | 1ea5728dd17 |
hex | 109c212905b |
1141422329947 has 2 divisors, whose sum is σ = 1141422329948. Its totient is φ = 1141422329946.
The previous prime is 1141422329857. The next prime is 1141422329951. The reversal of 1141422329947 is 7499232241411.
It is a strong prime.
It is an emirp because it is prime and its reverse (7499232241411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1141422329947 - 215 = 1141422297179 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1141422329947.
It is not a weakly prime, because it can be changed into another prime (1141422321947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570711164973 + 570711164974.
It is an arithmetic number, because the mean of its divisors is an integer number (570711164974).
Almost surely, 21141422329947 is an apocalyptic number.
1141422329947 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141422329947 is an equidigital number, since it uses as much as digits as its factorization.
1141422329947 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 870912, while the sum is 49.
It can be divided in two parts, 1141422 and 329947, that added together give a square (1471369 = 12132).
The spelling of 1141422329947 in words is "one trillion, one hundred forty-one billion, four hundred twenty-two million, three hundred twenty-nine thousand, nine hundred forty-seven".
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