Base | Representation |
---|---|
bin | 110101001001101111… |
… | …1000101111001001011 |
3 | 101220121212020011211211 |
4 | 1222103133011321023 |
5 | 3332231222113201 |
6 | 124234204233551 |
7 | 11150404114135 |
oct | 1522337057113 |
9 | 356555204754 |
10 | 114143551051 |
11 | 44454071372 |
12 | 1a15653b8b7 |
13 | a9c0aa006a |
14 | 574b624055 |
15 | 2e80c76651 |
hex | 1a937c5e4b |
114143551051 has 4 divisors (see below), whose sum is σ = 118079535600. Its totient is φ = 110207566504.
The previous prime is 114143551019. The next prime is 114143551121. The reversal of 114143551051 is 150155341411.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 150155341411 = 1721 ⋅87248891.
It is a cyclic number.
It is not a de Polignac number, because 114143551051 - 25 = 114143551019 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114143581051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1967992231 + ... + 1967992288.
It is an arithmetic number, because the mean of its divisors is an integer number (29519883900).
Almost surely, 2114143551051 is an apocalyptic number.
114143551051 is a deficient number, since it is larger than the sum of its proper divisors (3935984549).
114143551051 is an equidigital number, since it uses as much as digits as its factorization.
114143551051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3935984548.
The product of its (nonzero) digits is 6000, while the sum is 31.
Adding to 114143551051 its reverse (150155341411), we get a palindrome (264298892462).
The spelling of 114143551051 in words is "one hundred fourteen billion, one hundred forty-three million, five hundred fifty-one thousand, fifty-one".
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