Base | Representation |
---|---|
bin | 10101010000110001… |
… | …11001100011000011 |
3 | 1002110112101210220221 |
4 | 22220120321203003 |
5 | 141334222042201 |
6 | 5124411443511 |
7 | 552606121441 |
oct | 125030714303 |
9 | 32415353827 |
10 | 11415034051 |
11 | 4928542043 |
12 | 2266a56597 |
13 | 10cbc00c25 |
14 | 7a4069b91 |
15 | 46c2224a1 |
hex | 2a86398c3 |
11415034051 has 2 divisors, whose sum is σ = 11415034052. Its totient is φ = 11415034050.
The previous prime is 11415034031. The next prime is 11415034069. The reversal of 11415034051 is 15043051411.
It is a strong prime.
It is an emirp because it is prime and its reverse (15043051411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11415034051 - 27 = 11415033923 is a prime.
It is not a weakly prime, because it can be changed into another prime (11415034031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5707517025 + 5707517026.
It is an arithmetic number, because the mean of its divisors is an integer number (5707517026).
Almost surely, 211415034051 is an apocalyptic number.
11415034051 is a deficient number, since it is larger than the sum of its proper divisors (1).
11415034051 is an equidigital number, since it uses as much as digits as its factorization.
11415034051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 11415034051 its reverse (15043051411), we get a palindrome (26458085462).
The spelling of 11415034051 in words is "eleven billion, four hundred fifteen million, thirty-four thousand, fifty-one".
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