Base | Representation |
---|---|
bin | 110101001011011100… |
… | …1001110000111111001 |
3 | 101220202211211021120102 |
4 | 1222112321032013321 |
5 | 3332340341412103 |
6 | 124244010005145 |
7 | 11152000130654 |
oct | 1522671160771 |
9 | 356684737512 |
10 | 114200732153 |
11 | 44483377382 |
12 | 1a1717167b5 |
13 | a9cc8a0c31 |
14 | 575506a89b |
15 | 2e85cbde88 |
hex | 1a96e4e1f9 |
114200732153 has 4 divisors (see below), whose sum is σ = 114201997968. Its totient is φ = 114199466340.
The previous prime is 114200732137. The next prime is 114200732167. The reversal of 114200732153 is 351237002411.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 351237002411 = 313 ⋅1122162947.
It is a cyclic number.
It is not a de Polignac number, because 114200732153 - 24 = 114200732137 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114200732123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 486251 + ... + 681792.
It is an arithmetic number, because the mean of its divisors is an integer number (28550499492).
Almost surely, 2114200732153 is an apocalyptic number.
It is an amenable number.
114200732153 is a deficient number, since it is larger than the sum of its proper divisors (1265815).
114200732153 is an equidigital number, since it uses as much as digits as its factorization.
114200732153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1265814.
The product of its (nonzero) digits is 5040, while the sum is 29.
Adding to 114200732153 its reverse (351237002411), we get a palindrome (465437734564).
The spelling of 114200732153 in words is "one hundred fourteen billion, two hundred million, seven hundred thirty-two thousand, one hundred fifty-three".
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