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11420123043331 is a prime number
BaseRepresentation
bin1010011000101111010001…
…1000001001011000000011
31111102202100000021120021101
42212023310120021120003
52444101402444341311
640142155422235231
72256035203136212
oct246136430113003
944382300246241
1011420123043331
113703279810632
121345368125b17
1364abb3a8b212
142b6a460cd079
1514c0e4a25ec1
hexa62f4609603

11420123043331 has 2 divisors, whose sum is σ = 11420123043332. Its totient is φ = 11420123043330.

The previous prime is 11420123043293. The next prime is 11420123043337. The reversal of 11420123043331 is 13334032102411.

It is a strong prime.

It is an emirp because it is prime and its reverse (13334032102411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11420123043331 - 29 = 11420123042819 is a prime.

It is a super-2 number, since 2×114201230433312 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11420123043331.

It is not a weakly prime, because it can be changed into another prime (11420123043337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5710061521665 + 5710061521666.

It is an arithmetic number, because the mean of its divisors is an integer number (5710061521666).

Almost surely, 211420123043331 is an apocalyptic number.

11420123043331 is a deficient number, since it is larger than the sum of its proper divisors (1).

11420123043331 is an equidigital number, since it uses as much as digits as its factorization.

11420123043331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 11420123043331 its reverse (13334032102411), we get a palindrome (24754155145742).

The spelling of 11420123043331 in words is "eleven trillion, four hundred twenty billion, one hundred twenty-three million, forty-three thousand, three hundred thirty-one".