Base | Representation |
---|---|
bin | 11001111101110111001000… |
… | …000001010001110000001011 |
3 | 112222100121221112202111121101 |
4 | 121331313020001101300023 |
5 | 104432042142222231103 |
6 | 1042515441344522231 |
7 | 33024560666461012 |
oct | 3175671001216013 |
9 | 488317845674541 |
10 | 114202241211403 |
11 | 3342a997a10294 |
12 | 109851ab620377 |
13 | 4b952c0819747 |
14 | 202b5bcc89a79 |
15 | d309e079ea1d |
hex | 67ddc8051c0b |
114202241211403 has 4 divisors (see below), whose sum is σ = 114290838762120. Its totient is φ = 114113643660688.
The previous prime is 114202241211329. The next prime is 114202241211451. The reversal of 114202241211403 is 304112142202411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114202241211403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114202241211103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44298773425 + ... + 44298776002.
It is an arithmetic number, because the mean of its divisors is an integer number (28572709690530).
Almost surely, 2114202241211403 is an apocalyptic number.
114202241211403 is a deficient number, since it is larger than the sum of its proper divisors (88597550717).
114202241211403 is an equidigital number, since it uses as much as digits as its factorization.
114202241211403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88597550716.
The product of its (nonzero) digits is 3072, while the sum is 28.
Adding to 114202241211403 its reverse (304112142202411), we get a palindrome (418314383413814).
The spelling of 114202241211403 in words is "one hundred fourteen trillion, two hundred two billion, two hundred forty-one million, two hundred eleven thousand, four hundred three".
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