Base | Representation |
---|---|
bin | 10101010001100001… |
… | …10110000101111001 |
3 | 1002110222012201202121 |
4 | 22220300312011321 |
5 | 141342323430403 |
6 | 5125154201241 |
7 | 553013354554 |
oct | 125060660571 |
9 | 32428181677 |
10 | 11421311353 |
11 | 493103a2a1 |
12 | 2268b83221 |
13 | 11002bb1ca |
14 | 7a4c2169b |
15 | 46ca623bd |
hex | 2a8c36179 |
11421311353 has 2 divisors, whose sum is σ = 11421311354. Its totient is φ = 11421311352.
The previous prime is 11421311303. The next prime is 11421311383. The reversal of 11421311353 is 35311312411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8554030144 + 2867281209 = 92488^2 + 53547^2 .
It is a cyclic number.
It is not a de Polignac number, because 11421311353 - 29 = 11421310841 is a prime.
It is a super-3 number, since 3×114213113533 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (11421311303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5710655676 + 5710655677.
It is an arithmetic number, because the mean of its divisors is an integer number (5710655677).
Almost surely, 211421311353 is an apocalyptic number.
It is an amenable number.
11421311353 is a deficient number, since it is larger than the sum of its proper divisors (1).
11421311353 is an equidigital number, since it uses as much as digits as its factorization.
11421311353 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1080, while the sum is 25.
Adding to 11421311353 its reverse (35311312411), we get a palindrome (46732623764).
The spelling of 11421311353 in words is "eleven billion, four hundred twenty-one million, three hundred eleven thousand, three hundred fifty-three".
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