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11421368387993 is a prime number
BaseRepresentation
bin1010011000110011111010…
…0110110000100110011001
31111102212112210121121222202
42212030332212300212121
52444111430301403433
640142523150255545
72256111104322524
oct246147646604631
944385483547882
1011421368387993
1137038587784a3
1213456551b75b5
1364b051a9ab55
142b6b23663bbb
1514c16901bee8
hexa633e9b0999

11421368387993 has 2 divisors, whose sum is σ = 11421368387994. Its totient is φ = 11421368387992.

The previous prime is 11421368387983. The next prime is 11421368388007. The reversal of 11421368387993 is 39978386312411.

11421368387993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7561196556169 + 3860171831824 = 2749763^2 + 1964732^2 .

It is a cyclic number.

It is not a de Polignac number, because 11421368387993 - 210 = 11421368386969 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (11421368387983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5710684193996 + 5710684193997.

It is an arithmetic number, because the mean of its divisors is an integer number (5710684193997).

Almost surely, 211421368387993 is an apocalyptic number.

It is an amenable number.

11421368387993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11421368387993 is an equidigital number, since it uses as much as digits as its factorization.

11421368387993 is an evil number, because the sum of its binary digits is even.

The product of its digits is 47029248, while the sum is 65.

The spelling of 11421368387993 in words is "eleven trillion, four hundred twenty-one billion, three hundred sixty-eight million, three hundred eighty-seven thousand, nine hundred ninety-three".