114214005331 has 2 divisors, whose sum is σ = 114214005332. Its totient is φ = 114214005330.

The previous prime is 114214005307. The next prime is 114214005361. The reversal of 114214005331 is 133500412411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 114214005331 - 2²¹ = 114211908179 is a prime.

It is a super-3 number, since 3×114214005331³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 114214005296 and 114214005305.

It is not a weakly prime, because it can be changed into another prime (114214005361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57107002665 + 57107002666.

It is an arithmetic number, because the mean of its divisors is an integer number (57107002666).

Almost surely, 2^114214005331 is an apocalyptic number.

114214005331 is a deficient number, since it is larger than the sum of its proper divisors (1).

114214005331 is an equidigital number, since it uses as much as digits as its factorization.

114214005331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 114214005331 its reverse (133500412411), we get a palindrome (247714417742).

The spelling of 114214005331 in words is "one hundred fourteen billion, two hundred fourteen million, five thousand, three hundred thirty-one".