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1142141420153 is a prime number
BaseRepresentation
bin10000100111101100111…
…011110000001001111001
311001012001210120201102202
4100213230323300021321
5122203101200421103
62232405330235545
7145342220613536
oct20475473601171
94035053521382
101142141420153
1140041a068758
12165430a25bb5
138391b6bb746
143d3cc223d8d
151ea9a482988
hex109ecef0279

1142141420153 has 2 divisors, whose sum is σ = 1142141420154. Its totient is φ = 1142141420152.

The previous prime is 1142141420117. The next prime is 1142141420159. The reversal of 1142141420153 is 3510241412411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 842131076329 + 300010343824 = 917677^2 + 547732^2 .

It is a cyclic number.

It is not a de Polignac number, because 1142141420153 - 218 = 1142141158009 is a prime.

It is a super-2 number, since 2×11421414201532 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1142141420159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571070710076 + 571070710077.

It is an arithmetic number, because the mean of its divisors is an integer number (571070710077).

Almost surely, 21142141420153 is an apocalyptic number.

It is an amenable number.

1142141420153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1142141420153 is an equidigital number, since it uses as much as digits as its factorization.

1142141420153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 29.

Adding to 1142141420153 its reverse (3510241412411), we get a palindrome (4652382832564).

The spelling of 1142141420153 in words is "one trillion, one hundred forty-two billion, one hundred forty-one million, four hundred twenty thousand, one hundred fifty-three".