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1142144004433 is a prime number
BaseRepresentation
bin10000100111101101000…
…101100111000101010001
311001012001222110000101211
4100213231011213011101
5122203102331120213
62232405501500121
7145342251566065
oct20475505470521
94035058400354
101142144004433
11400420573323
12165431871641
138391c0b4ac3
143d3cc6d7aa5
151ea9a7e353d
hex109ed167151

1142144004433 has 2 divisors, whose sum is σ = 1142144004434. Its totient is φ = 1142144004432.

The previous prime is 1142144004401. The next prime is 1142144004437. The reversal of 1142144004433 is 3344004412411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1140673128529 + 1470875904 = 1068023^2 + 38352^2 .

It is a cyclic number.

It is not a de Polignac number, because 1142144004433 - 25 = 1142144004401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1142144004395 and 1142144004404.

It is not a weakly prime, because it can be changed into another prime (1142144004437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571072002216 + 571072002217.

It is an arithmetic number, because the mean of its divisors is an integer number (571072002217).

Almost surely, 21142144004433 is an apocalyptic number.

It is an amenable number.

1142144004433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1142144004433 is an equidigital number, since it uses as much as digits as its factorization.

1142144004433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 1142144004433 its reverse (3344004412411), we get a palindrome (4486148416844).

The spelling of 1142144004433 in words is "one trillion, one hundred forty-two billion, one hundred forty-four million, four thousand, four hundred thirty-three".