Base | Representation |
---|---|
bin | 110101001100000010… |
… | …0000010011011011011 |
3 | 101220211012201201102001 |
4 | 1222120010002123123 |
5 | 3332410402020201 |
6 | 124245550221431 |
7 | 11152325625301 |
oct | 1523004023333 |
9 | 356735651361 |
10 | 114220345051 |
11 | 4449345288a |
12 | 1a1781b4877 |
13 | aa0397a0b7 |
14 | 57578d4271 |
15 | 2e87895301 |
hex | 1a981026db |
114220345051 has 4 divisors (see below), whose sum is σ = 114221152552. Its totient is φ = 114219537552.
The previous prime is 114220345049. The next prime is 114220345073. The reversal of 114220345051 is 150543022411.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 150543022411 = 19 ⋅7923316969.
It is a cyclic number.
It is not a de Polignac number, because 114220345051 - 21 = 114220345049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114220345021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 129465 + ... + 495178.
It is an arithmetic number, because the mean of its divisors is an integer number (28555288138).
Almost surely, 2114220345051 is an apocalyptic number.
114220345051 is a deficient number, since it is larger than the sum of its proper divisors (807501).
114220345051 is an equidigital number, since it uses as much as digits as its factorization.
114220345051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 807500.
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 114220345051 its reverse (150543022411), we get a palindrome (264763367462).
The spelling of 114220345051 in words is "one hundred fourteen billion, two hundred twenty million, three hundred forty-five thousand, fifty-one".
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